Assign Y

July 3, 2015

The first solution uses arithmetic:

(define (solve1 a b x)
  (+ (* (- 1 x) a) (* x b)))

> (solve1 13 17 0)
13
> (solve1 13 17 1)
17

If x is 0, then the second clause is 0 and the sum is a; if x is 1, then the first clause is 0 and the sum is b. The second solution uses an array:

(define (solve2 a b x)
  (vector-ref (vector a b) x))

> (solve2 13 17 0)
13
> (solve2 13 17 1)
17

The two numbers a and b are stored in a array that is indexed by variable x. You can run the program at http://ideone.com/FqvamB.

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Posted by programmingpraxis
Filed in Exercises
6 Comments »

6 Responses to “Assign Y”

  1. Lucas A. Brown said
    July 3, 2015 at 9:50 AM

    In Python:

    y = (1-x) * a + x * b
y = [a,b][x]

    In C:

    uint64_t a=/* blah */, b=/* blah */, x=/* 0 or 1 */, y;
x = (x <<  1) | x; x = (x <<  2) | x; x = (x <<  4) | x;
x = (x <<  8) | x; x = (x << 16) | x; x = (x << 32) | x;
y = (b & x) | (a & (~x));

    This is basically a translation of the first Python line for 64-bit data. If you’re feeling pedantic, you might declare the bit-twiddling to be both arithmetic and conditional, but it’s branch-free and technically avoids the arithmetic operators.

  2. Gil Martinez said
    July 3, 2015 at 1:22 PM

    In Racket:

    ; arithmetic solution
(let ((a 2) (b 3) (x 1))
 (let ((y (+ (* a (modulo x 2))
                 (* b (modulo (add1 x) 2)))))
  y))

; non-arithmetic solution
(let ((a 2) (b 3) (x 1))
 (let ((y (or (and (= 0 x)
                          a)
                  b)))
  y))

    The arithmetic solution uses modular addition on x to determine the coefficients of a and b. The resulting terms are added to produce b.

    The non-arithmetic solution uses logical operators.

  3. captain falcom said
    July 3, 2015 at 3:18 PM

    I can’t decide if this is cheating or not. Both a and b get assigned to something, which might not be the intended outcome.

    “`
    vars = [nil, nil]
    vars[x] = y
    a, b = vars
    “`

  4. Mike said
    July 4, 2015 at 6:32 AM

    Is it okay to answer that the problem is under specified? What if x isn’t 0 or 1? ;-)

    # equation of a line with slope (b-a)/(1-0) and y-intercept of a
# this works if x isn't an integer, and assigns some value even if x isn't 0 or 1.
y = (b - a)*x + a


# standard short circuit logical expression - no arithmetic operators
y = x and b or a


# Don't think I've seen this answer before
try:
	y = b // x
except ZeroDivisionError:
	y = a
  5. programmingpraxis said
    July 4, 2015 at 2:40 PM

    @MIke: x must be either 0 or 1. I’ve changed the problem statement to make that explicit.

  6. Brett Warrem said
    July 6, 2015 at 9:45 AM

    I derived a formula ((a**(1-x)/b**x)**(1-2*x)) that assigns a or b to y depending on x:

    def assign_y(x, a, b):
    y = int((a**(1-x)/b**x)**(1-2*x))
    return y

    if __name__ == “__main__”:
    print(assign_y(0, 3, 2))
    print(assign_y(1, 3, 2))

    Results:
    3
    2

    As for the second part of the question; not a franking clue.

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