Approximate Squaring

June 8, 2021

Here is a function to perform approximate squaring:

(define (asq x)
  (define (sq x) (* x (ceiling x)))
  (let loop ((x (sq x)) (xs (list x)))
    (if (integer? x)
        (reverse (cons x xs))
        (loop (sq x) (cons x xs)))))

> (asq 8/7)
(8/7 16/7 48/7 48)
> (asq 10/6)
(5/3 10/3 40/3 560/3 104720/3 3655461040/3
     1484710602474311520)

And here we build a table of iterations with a common denominator:

(define (asq-table d)
  (do ((n (+ d 1) (+ n 1))) ((= n (+ d d)))
    (let ((xs (asq (/ n d))))
      (display n) (display " ")
      (display (- (length xs) 1)) (display " ")
      (display (car (reverse xs))) (newline))))

> (asq-table 6)
7 2 7
8 2 8
9 1 3
10 6 1484710602474311520
11 3 220
> (asq-table 8)
9 4 2268
10 3 60
11 9 732080866432229367801083417675404689703681113835718829583758556242941523077452534455211024511178371450604417810705361050
12 1 3
13 2 13
14 2 14
15 2 15

Already you can see the chaotic nature of approximate squaring. If you want to see some really big numbers, look at the table for 5 or 7.

You can run the program at <a href=”https://ideone.com/31ZGUO”>https://ideone.com/31ZGUO</a>.

Posted by programmingpraxis

Filed in Exercises

6 Comments »

6 Responses to “Approximate Squaring”

Zack said
June 8, 2021 at 1:04 PM
Nifty little drill. I suppose some people have way too much time on their hands, writing papers like this!

Here is my take on this using Julia: https://pastebin.com/TtiyB0Wu

Globules said

June 10, 2021 at 6:53 AM

Here’s a Haskell version.

import Data.Ratio (denominator, numerator)
import System.Environment (getArgs)

approxSq :: Rational -> Rational
approxSq x = x * toRational (ceiling x :: Integer)

iterApproxSq :: Rational -> Integer
iterApproxSq = numerator . head . iterateUntil isInteger approxSq
  where isInteger = (== 1) . denominator
        iterateUntil p f = dropWhile (not . p) . drop 1 . iterate f

main :: IO ()
main = do
  rs <- getArgs
  mapM_ (print . iterApproxSq . read) rs

$ ./approxsq 8%7 3%2 5%2 7%2 9%2 11%2 13%2 15%2 17%2 19%2 3%3 4%3 5%3
48
3
60
14
268065
33
2093
60
1204154941925628
95
1
8
1484710602474311520

Jared said

June 13, 2021 at 8:13 PM

Lisp:
(defun approximate-square (number)
(loop
for n = number then (* n (ceiling n))
when (integerp n)
do (return n)))

> (mapcar #'approximate-square '(8/7 3/2 5/2 7/2 9/2 11/2 13/2 15/2 17/2 19/2 3/3 4/3 5/3))
(48 3 60 14 268065 33 2093 60 1204154941925628 95 1 8 1484710602474311520)

Daniel said

June 21, 2021 at 6:28 PM

Here’s a solution in Python.

def approx_squaring(n, d):
    while n % d:
        n *= (n + d - 1) // d
    return n // d

print(approx_squaring(8, 7))
print(approx_squaring(10, 6))
print(approx_squaring(6, 5))

Output:

48
1484710602474311520
9532960047385704656...9010186950239453184

Daniel said

June 21, 2021 at 7:42 PM

Here’s a solution in C using GMP.

// $ gcc -o approx_squaring approx_squaring.c -lgmp

#include <stdlib.h>

#include <gmp.h>

int main(int argc, char* argv[]) {
  if (argc != 3) return EXIT_FAILURE;
  mpz_t n;
  mpz_init(n);
  mpz_set_str(n, argv[1], 10);
  mpz_t d;
  mpz_init(d);
  mpz_set_str(d, argv[2], 10);
  mpz_t q;
  mpz_init(q);
  while (!mpz_divisible_p(n, d)) {
    mpz_cdiv_q(q, n, d);
    mpz_mul(n, n, q);
  }
  mpz_divexact(n, n, d);
  gmp_printf("%Zd\n", n);
  mpz_clear(n);
  mpz_clear(d);
  mpz_clear(q);
  return EXIT_SUCCESS;
}

Example usage:

$ ./approx_squaring 8 7
48
$ ./approx_squaring 10 6
1484710602474311520
$ ./approx_squaring 6 5
9532960047385704656...9010186950239453184

Approximate Squaring - 2url.biz said
October 11, 2022 at 12:03 PM
[…] is to write a program that iterates approximate squaring. When you are finished, you are welcome to read or run a suggested solution, or to post your own solution or discuss the exercise in the comments […]

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