## Dollar Format

### September 30, 2016

We have a simple task today, a function that formats a number in dollar format. A number like 1234567.8912 should be rounded to two positions after the decimal point, have commas inserted every three positions before the decimal point, and have a dollar sign prepended; thus, the function should format 1234567.8912 as \$1,234,567.89.

Your task is to write a function that returns numbers in dollar format; if your language provides such a facility natively, you are not permitted to use it. When you are finished, you are welcome to read or run a suggested solution, or to post your own solution or discuss the exercise in the comments below.

Pages: 1 2

### 6 Responses to “Dollar Format”

1. matthew said
```(display (dollar 1234567.9999)) (newline)
\$1,234,567.100
```
2. tchaardge said

Hi

/* 1234567.8912 as \$1,234,567.89 */
function f\$(f) {
/** MATH **/
/* 100,033 -> 10003,3 */
f = f*100
/* 10003,3 -> 10003 */
f = Math.round(f)
/* 10003 -> 100,03 */
f = f / 100.0

/** SRING **/
/* 100,03 -> [1,0,0,’,’,0,3] */
var ent = f.toString().split(‘.’)[0]
var dec = f.toString().split(‘.’)[1]
dec = dec+’00’
dec = dec.substr(0,3)
ent = ent.split(”)
ent = ent.reverse().map(function(c,i) {
if(i % 3 == 0 && i != 0)
return c+’,’
return c
}).reverse().join(”)
return ‘\$’+ent+’.’+dec

}

console.log(f\$(1000.200))

Thanks

3. xem said

ES6:

to\$ = n => “\$”+n.toFixed(2).replace(/(\d)(?=(\d\d\d)+\.)/g,”\$1,”);

4. maximeeuziere said

ES6, shorter:

to\$ = n => “\$”+n.toFixed(2).replace(/.(?=(…)+\.)/g,”\$&,”);

5. Alex B. said

Python 3 solution without using round() or str.format():

```def dollars(n):
'''Format a number as a dollar amount string'''
n = int(n*100)
s = str(n)
i, d = s[:-2], s[-2:]
l = [i[(c-3 if c >= 3 else 0):c] for c in range(len(i),0,-3)]
o = '.'.join((','.join(reversed(l)),d))
return ''.join(('\$', o))
```
6. V said

In Ruby

```
def format(amount)
decimal, fraction = amount.round(2).to_s.split('.')
decimal_part = decimal.
chars.
reverse.
each_slice(3).
map { |xs| xs.reverse.join }.
reverse.
join(",")

"\$" + decimal_part + "." + fraction.ljust(2, "0")
end

```