A cyclical list has no beginning and no end; Chez Scheme writes it like this:

#0=(1 2 3 . #0#)

Your task is to write a program that removes an item from a cyclical list; if the item is not present in the cyclical list, it should remain unchanged. When you are finished, you are welcome to read or run a suggested solution, or to post your own solution or discuss the exercise in the comments below.


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